Web0.5 molal aqueous solution of a weak acid (HX) is 20% Ionized. If Kr of water is 1.86 K kg mol-1, the lowering in freezing point of solution is 1.12 K. Explanation: \[\ce{HX <=> H+ +. Web0.5 molal aqueous solution of a weak acid (HX) is 20 % ionised. If Kf for water is 1.86 K Kg mol-1, the lowering in freezing point of the solution is. Q. 0.5 molal aqueous solution of a.
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WebA 0.1 molal aqueous solution of a weak monobasic acid is 40% ionized. The freezing point of the solution will be ( K f ( w a t er ) = 1.8 6 ° K / m ) 1107 25 Report Error WebA `0.5`molal aqueous solution of a weak acid (HX) is 20 per cent ionized.The lowering in freezing point of this solution is `(K_(f)=1.86 \"K/m for water\")`. WebA `0.1` molal aqueous solution of a weak acid is `30%` ionized. If `K_(f)` for water is `1.86^(@)C//m`, the freezing point of the solution will be. WebFor the reaction of a general weak acid in water, #"HA"(aq) + "H"_2"O"(l) rightleftharpoons "H"_3"O"^(+)(aq) + "A"^(-)(aq)# If it is #2.5%# ionized, then the fraction. Web2 molal solution of a weak acid HA has a freezing point of 3.885°C. The degree of dissociation of this acid is ...... x 10–3. (Round off to the Nearest Integer).. WebA 0.2 molal aqueous solution of a weak acid (HX) is 20% ionised. The freezing point of this solution is (Given for water) Q. 0.5 molal aqueous solution of a weak acid (HX) is 20%. Web0.5 molal aqueous solution of a weak acid h x is 20% ionized. If k f for water is 1.86 k k g m o l 1 , - Brainly.in. Find an answer to your question 0.5 molal aqueous.
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\( 0.5 \) molal aqueous solution of a weak acid \( (\mathrm{HX}) \) is \( 20 \% \) ionised. If \( K_{f} \) for water is \( 1.86 \mathrm{~K} \mathrm{~kg} \mathrm{~mol}^{-1} \), the lowering in freezing point of the solution is
(a) \( 0.56 \mathrm{~K} \)
(b) \( 1.12 \mathrm{~K} \)
(c) \( -0.56 \mathrm{~K} \)
(d) \( -1.12 \mathrm{~K} \)
\( (2007) \)
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