Webprove sin20*sin40*sin60*sin80. proof:-. sin3A = 3sinA - 4sin^3 (A) sin (60) = 3*sin (20) - 4*sin^3 (20) put sin (60) = (root (3))/2 and sin (20) as y. (root (3))/2 = 3y - 4y^3. y^3 - 3/4y. WebProve that sin 20° sin 40° sin 60° sin 80° =3/16 - 1207071. Two nunbers are in the ratio 2: 5. if the sum of the numbers is 49, find the numbers Websin(20) sin(40) sin (60) sin (80) substitute sin(60) = √3 /2 √3/2 [ sin(20) sin(40) sin(80) ] = (√3/2) sin(20) [ sin(40) sin(80) ] use the formula sin A sin B = (1/2) [ cos(A - B) -.
Prove That Sin20 Sin40 Sin60 Sin80 3 16, Exact value of sin20 sin40 sin60 sin80 is 3 over 16, 12.75 MB, 09:17, 25,078, Anil Kumar, 2017-12-05T10:32:32.000000Z, 19, how to prove that sin 20 sin 40 sin 60 sin 80 equal to 3 by 16 - Brainly.in, brainly.in, 1405 x 986, jpeg, sin prove value equal brainly, 20, prove-that-sin20-sin40-sin60-sin80-3-16, KAMPION
WebExplanation: x = 16sin20 ⋅ sin40 ⋅ sin60 ⋅ sin80. = 16 ⋅ √3 2 ⋅ sin80⋅ sin40⋅ sin20. = 8√3 ⋅ sin80⋅ sin40⋅ sin20. = 4√3 ⋅ (cos40 −cos120) ⋅ sin20. = 4√3 ⋅ (cos40. WebProve the following : sin 20° sin 40° sin 60° sin 80° = 316 - Mathematics and Statistics | Shaalaa.com. Textbook Solutions 9077. Important Solutions 19. Question Bank Solutions. WebProve that : sin 20° sin 40° sin 60° sin 80° = 3/16. LIVE Course for free. Rated by 1 million+ students Get app now Login. Remember. Register; Test; JEE; NEET; Home;. Webanswered Jul 29, 2021 by Anaswara (31.5k points) selected Aug 9, 2021 by Dheeya. Best answer. L.H.S. = 1 2 1 2 (2sin80°sin20°) sin40°√3 2 3 2. = 3 16 3 16. Websin20 sin40 sin60 sin80 = 3/16prove that sin20 sin40 sin60 sin80=3/16 class 11Prove that sin20 sin40 sin60 sin80=3 divide by 16 WebExplanation: Let , X = sin20∘sin40∘sin60∘sin80∘. ∴ X = 1 2 (sin60∘sin20∘)(2sin80∘sin40∘) Using , Product Identity. 2sinxsiny = cos(x −y) − cos(x +. WebProve that: sin 20^∘ sin 40^∘ sin 60^∘ sin 80^∘ = 316. Class 11. >> Maths. >> Trigonometric Functions. >> Trigonometric Functions of Sum and Difference of Two angles. >> Prove. WebProve that $$\frac{\sin 40^\circ}{\sin 80^\circ} +\frac{\sin 80^\circ}{\sin 20^\circ} -\frac{\sin 20^\circ}{\sin 40^\circ} =3.$$ I tried taking the least common multiple of the. WebSolution. Verified by Toppr. sin20°sin40°sin60°sin80°. =sin(30−10)+sin(30+10)× 2 3sin(90−10) = 2.
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Here sin20°sin40°sin60°sin80°=3/16
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sin20 sin40 sin 60 sin80 = 3/16
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