WebQ.18 How much momentum will a dumb-bell of mass 10 kg transfer to the floor if it falls from a height of 80 cm? Take its downward acceleration to be 10 m s. WebRight Answer is: A SOLUTION Mass of the dumbbell, m= 10 kg Distance covered by the dumbbell, s =80cm = 0.8m Acceleration in the downward direction,a= 10 ms−2 Initial.
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WebAccording to the third equation of motion. v2−u2 =2as ⇒ v=√u2+(2×a×s) ⇒ v=√0+(2×10×0.8) = 4 ms−1 . Hence, the momentum (p) with which the dumbbell hits the floor is. p =m×v=. WebGiven, mass of the dumb-bell (m) = 10 kg. Distance covered (s) = 80 cm = 0.8 m. Initial velocity (u) = 0 . Acceleration (a) = \( 10 m/s^2 \) Momentum of the dumb-bell when it hits. WebMass of the dumbbell, m = 10 kg. Distance, s = 80 cm = 80 / 100 = 0.8 m. Acceleration, a = 10 m/s 2. Initial velocity of the dumbbell, u = 0. Final velocity of the dumbbell = v. Using. WebAnswer: Mass of the dumbbell, m=10 kg Distance covered by the dumbbell, s=80 cm=0.8 m Acceleration in the downward direction, a=10 m/s2 Initial... Online. WebHello buddyIn this video I tell about law f inertia." 18. How much momentum will a dumb-bell of mass 10 kg transfer to the floor if it falls from a height o... WebGiven, mass of the dumb-bell (m) = 10kg. Distance covered (s) = 80cm = 0.8m. Initial velocity (u) = 0 (it is dropped from a position of rest) Acceleration (a) = 10m s^{-2}. WebThe momentum of the dumbbell is given by: p = mv. p is its momentum, m is its mass, and v is its velocity. Given values: m = 10kg. v = 4m/s (from previous. Webv is the final velocity of the dumb-bell and u will be its initial velocity. We will take u to be zero as the body starts from rest and we will take the downward direction as. WebMass of dumb-bell = 10 kg Height, h = 80 cm = 0.8 m a = 10 m/s^2 u = 0 v2– u2= 2 as v2– (0)^2= 2 × 10 × 0.8 v2= 16 v = 4 m/s Momentum p = mv = 10 × 4 = 40 kgm/s Thanks
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Q.18 How much momentum will a dumb-bell of mass 10 kg transfer to the floor if it falls from a height of 80 cm? Take its downward acceleration to be 10 m s-2.
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