WebQuestion 12:How much charge is required for the following reductions: (i) 1 mol of Al 3+ to Al. (ii) 1 mol of Cu 2+ to Cu. (iii) 1 mol of MnO 4– to Mn 2+. Answer:(i) Formula. WebHow much charge is required for the following reduction of (i) 1 mol of Al 3+ to Al (ii) 1 mol of Cu 2+ to Cu (iii) 1 mol of MnO 4 – to Mn 2+ (i) Al 3+ + 3e – → Al 1 mol Al 3+ for.
How Much Charge Is Required For The Following Reduction, How much Charge is required for the following reductions `:` `a. 1 mol of Al^(3+) to Al` `b.` ` ..., 6.36 MB, 04:38, 5,260, Doubtnut, 2019-09-24T08:02:49.000000Z, 19, How much charge is required for the following reductions: (i) 1 mol of, www.doubtnut.com, 1200 x 677, png, , 20, how-much-charge-is-required-for-the-following-reduction, KAMPION
WebAnswer: Formula required charge n × F. n = difference of charge on ions. F is constant and equal to 96487 Coulombs. Here n = 3. Hence required charge = 3 ×. WebHow much charge is required for the following reduction of (i) 1 mol of Al3+ to Al (ii) 1 mol of Cu2+ to Cu (iii) 1 mol of MnO4– to Mn2+ from Chemistry Electrochemistry Class 12 CBSE. WebHow much charge is required for the following reductions:i 1 mol of Al 3+ to Al.ii 1 mol of Cu 2+ to Cu.iii 1 mol of MnO 4 to Mn 2+. Byju's Answer. Standard XII. WebHow much charge is required for the following reductions Q.12: How much charge is required for the following reductions: (i) 1 mol of Al 3+ to Al. (ii) 1 mol of Cu 2+. WebHow much charge is required for the following reductions: 1 mol of Al3+ to Al. Department of Pre-University Education, Karnataka PUC Karnataka Science Class 12. Textbook. WebMnO4-(aq) + 8H++5e- → Mn2+(aq) + 6H2O. 1 mol 5 moles 1 mol Formula required charge n × F n = difference of charge on ions F is constant and equal to 96487 Coulombs. WebCall Us 07019-243-492; All Courses. All Courses IIT JEE . CLASS 11; CLASS 12; Dropper; NEET . CLASS 11; CLASS 12 WebQuantity of charge required for reducing 1 mole Cu2+toCu = 2F =2×96500 C= 1.93×105C. (iii) 1 mole M nO− 4 to M n2+. Electrode reaction: M nO− 4 ox.no of Mn=7 1 mol +5e− 5. Web3.12 How much charge is required for the following reductions: (ii) Answers (1) The equation can be written as:- Thus charge required is . Posted by Devendra Khairwa. View full.
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Subject Electrochemistry / How much charge is required for the following reduction / NCERT exc. Q. 12
Explanation of How Much Charge Is Required For The Following Reduction from the discussion earlier
Question From - NCERT Chemistry Class 12 Chapter 03 Question – 027 ELECTROCHEMISTRY CBSE, RBSE, UP, MP, BIHAR BOARD
QUESTION TEXT:-
How much Charge is required for the following reductions `:` `a. 1 mol of Al^(3+) to Al` `b.` ` 1 mol of Cu^(2+) to Cu` `c.` `1 mol of MnO_(4)^(-)` to `Mn^(2+)?`
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